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    <title>Operational Amplifiers: the Integrator Circuit</title>
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    <p align="right">08/22/04</p>
    <h2>ECE 1002</h2>
    <h3>Final Project</h3>
    <h3>Operational Amplifiers: the Integrator Circuit</h3>
    <p>
      <a href="../tutorials/final1234.avi">Camtasia Tutorial:
      Parts 1 through 4</a> (25,534 KB)
    </p>
    <p>
      <a href="../tutorials/final5678.avi">Camtasia Tutorial:
      Parts 5 through 8</a> (40,418 KB)
    </p>
    <p>
    <b>Note:</b>
    Viewing the equations in this document with Internet Explorer
    requires the installation of 
    <a href="../software/software.htm#MathPlayer"
    target="final_window">MathPlayer</a>
    software.</p>
    <p>The name 
    <i>operational amplifier</i>
    dates from the days when the main application of such
    circuits was performing integration and differentiation
    (calculus) for numerical simulation in analog computers,
    predecessors of contemporary digital computers. The
    operations of differentiation and integration were closely
    identified by the engineers of that day with the 
    <i>operational calculus</i>
    introduced by the pioneering electrical engineer, 
    <a
    href="http://www-groups.dcs.st-and.ac.uk/~history/Mathematicians/Heaviside.html"
     target="final_window">Oliver Heaviside</a>
    . Hence the name 
    <i>operational amplifier</i>
    , or 
    <i>op amp</i>
    , for short. (Subsequently, Heaviside's operational calculus
    was understood in terms of Laplace transforms, which you will
    study later.)</p>
    <p>An integrator circuit provides, in real time, an output
    signal that is the time integral of the input signal. Among
    many other applications, integrators today form the basis for
    extracting information from digital signals corrupted by
    noise, such as voices in digital phones. The application of
    operational amplifiers is far from limited to integrators,
    however. For instance, designers can make amplifiers with any
    particular gain they choose with a particular operational
    amplifier chip simply by adjusting the ratio of a couple of
    resistors connected externally to the chip.</p>
    <p>This example suggests how an operational amplifier chip,
    which includes the overwhelming majority of the circuit
    components (approaching 100 transistors and resistors on the
    chip) in the total circuit, can be mass produced and then
    customized for many specific purposes (realizing an amplifier
    with a particular gain, or an integrator, as examples) by the
    addition of a few external components.</p>
    <p>The versatility of the op amp creates a demand that
    justifies mass production at low cost. When the application
    of operational amplifiers was limited mainly to synthesizing
    integrators in analog computers, the cost of a single op amp
    was several hundred dollars. Now, because we realize their
    versatility and employ them in many diverse applications,
    demand is large enough to drive the price for some common
    types, such as the type 
    <i>741</i>
    that you will use in this project, below one dollar.</p>
    <p>In this project, you will see how to build, analyze and
    test an integrator circuit. The heart of the integrator you
    build will be a type 741 
    <i>operational amplifier</i>
    (or 
    <i>op amp</i>
    ) IC (integrated circuit) chip, represented by the triangle
    in the following circuit.</p>
    <p>
      <img border="0" src="./final_files/image002.jpg" />
    </p>
    <p>To accomplish to Final Project, you should know a few
    things about op amps and capacitors:</p>
    <ul type="disc">
      <li>The operational amplifier is an example of a 
      <i>differential amplifier</i>
      in that its output voltage is proportional to the 
      <i>difference</i>
      between the voltages at its two input terminals.</li>
      <li>To calculate the output voltage of an ideal op amp, we
      multiply the 
      <i>gain</i>
      , 
      <i>A</i>
      , of the ideal op amp by the 
      <i>difference</i>
      between the voltages at the two input terminals of the op
      amp. For an ideal op amp, therefore, we can write:</li>
    </ul>
    <p style='margin-left:1.0in'>
      <m:math>
        <m:semantics>
          <m:mrow>
            <m:msub>
              <m:mi>v</m:mi>
              <m:mrow>
                <m:mi>o</m:mi>
                <m:mi>u</m:mi>
                <m:mi>t</m:mi>
              </m:mrow>
            </m:msub>
            <m:mrow>
              <m:mo>(</m:mo>
              <m:mi>t</m:mi>
              <m:mo>)</m:mo>
            </m:mrow>
            <m:mtext>&#8201;</m:mtext>
            <m:mtext>&#8201;</m:mtext>
            <m:mo>=</m:mo>
            <m:mtext>&#8201;</m:mtext>
            <m:mi>A</m:mi>
            <m:mrow>
              <m:mo>(</m:mo>
              <m:mrow>
                <m:msub>
                  <m:mi>v</m:mi>
                  <m:mo>+</m:mo>
                </m:msub>
                <m:mrow>
                  <m:mo>(</m:mo>
                  <m:mi>t</m:mi>
                  <m:mo>)</m:mo>
                </m:mrow>
                <m:mtext>&#8201;</m:mtext>
                <m:mo>&#8722;</m:mo>
                <m:mtext>&#8201;</m:mtext>
                <m:msub>
                  <m:mi>v</m:mi>
                  <m:mo>&#8722;</m:mo>
                </m:msub>
                <m:mrow>
                  <m:mo>(</m:mo>
                  <m:mi>t</m:mi>
                  <m:mo>)</m:mo>
                </m:mrow>
              </m:mrow>
              <m:mo>)</m:mo>
            </m:mrow>
          </m:mrow>
        </m:semantics>
      </m:math>
    </p>
    <p>where 
    <i>v 
    <sub>+</sub>
    </i>
    ( 
    <i>t</i>
    ) is the voltage applied to the 
    <i>non-inverting input</i>
    (indicated by "+" in the figure above) of the op amp and 
    <i>v 
    <sub>-</sub>
    </i>
    ( 
    <i>t</i>
    ) is the voltage applied to the 
    <i>inverting input</i>
    (indicated by "-" in the figure above) of the op amp. The
    names of these inputs reflect the algebraic signs of their
    contributions to the output voltage of the op amp. The gain
    of op amps is large, typically 
    <i>10,000</i>
    or more. Thus, if the voltage difference at the input
    terminals is 
    <i>0.0001 V</i>
    and the gain 
    <i>A = 10000</i>
    , then the output voltage of the op amp is ( 
    <i>0.0001V</i>
    )( 
    <i>10000</i>
    ) 
    <i>= 1V</i>
    .</p>
    <ul type="disc">
      <li>An ideal op amp draws absolutely no current at either
      of its input terminals. The 
      <i>741</i>
      op amp draws a trickle of current at its inputs, but the
      currents are so small that, for simplicity, we can neglect
      them in our calculations without noticeable error.</li>
      <li>The voltage across an ideal capacitor, 
      <i>v 
      <sub>C</sub>
      </i>
      ( 
      <i>t</i>
      ), is related to the current through the ideal capacitor, 
      <i>i 
      <sub>C</sub>
      </i>
      ( 
      <i>t</i>
      ), by the following equation:</li>
    </ul>
    <p style='margin-left:1.0in'>
      <m:math>
        <m:semantics>
          <m:mrow>
            <m:msub>
              <m:mi>i</m:mi>
              <m:mi>C</m:mi>
            </m:msub>
            <m:mrow>
              <m:mo>(</m:mo>
              <m:mi>t</m:mi>
              <m:mo>)</m:mo>
            </m:mrow>
            <m:mo>=</m:mo>
            <m:mtext>&#8201;</m:mtext>
            <m:mi>C</m:mi>
            <m:mfrac>
              <m:mrow>
                <m:mi>d</m:mi>
                <m:msub>
                  <m:mi>v</m:mi>
                  <m:mi>C</m:mi>
                </m:msub>
              </m:mrow>
              <m:mrow>
                <m:mi>d</m:mi>
                <m:mi>t</m:mi>
              </m:mrow>
            </m:mfrac>
          </m:mrow>
        </m:semantics>
      </m:math>
    </p>
    <p style='margin-left:.5in'>where 
    <i>C</i>
    is the capacitance, a constant, of the ideal capacitor. Note
    that the relationship between the voltage and current for an
    ideal capacitor involves calculus and hence is more
    complicated than the relationship between the voltage and
    current for an ideal resistor, which is given by a purely
    algebraic equation, Ohm's Law. This complication does not
    affect the validity of KVL and KCL, which, as long as the
    frequency is not too high, hold for circuits regardless of
    what kinds of elements (inductors, transistors, ...) the
    circuits contain.</p>
    <p>Record and submit all your work for this Final Project in
    a Word document named 
    <i>final.doc</i>
    placed in a folder named 
    <i>final</i>
    on your hard disk. The first lines of this document should
    include the course number, the words Final Project, your
    name, your netID, and your e-mail address.</p>
    <ol>
      <li>
        <p>(10 points) Relate the output voltage, 
        <i>v 
        <sub>out</sub>
        </i>
        ( 
        <i>t</i>
        ), of the amplifier in the circuit above to the input
        voltage, 
        <i>v 
        <sub>in</sub>
        </i>
        ( 
        <i>t</i>
        ), which, as the input voltage, we consider given.</p>
        <p>To begin the solution process, first write 
        <i>6</i>
        equations in terms of the unknown voltages and currents 
        <i>v 
        <sub>out</sub>
        </i>
        ( 
        <i>t</i>
        ) 
        <i>, v 
        <sub>R</sub>
        </i>
        ( 
        <i>t</i>
        ) 
        <i>, i 
        <sub>R</sub>
        </i>
        ( 
        <i>t</i>
        ) 
        <i>, v 
        <sub>C</sub>
        </i>
        ( 
        <i>t</i>
        ) 
        <i>, i 
        <sub>C</sub>
        </i>
        ( 
        <i>t</i>
        ) 
        <i>, v 
        <sub>-</sub>
        </i>
        ( 
        <i>t</i>
        ). (Note that in the particular circuit above, the
        non-inverting input of the op amp is connected directly
        to ground so that 
        <i>v 
        <sub>+</sub>
        </i>
        ( 
        <i>t</i>
        ) is zero.) Write 
        <i>1</i>
        equation from 
        <i>KCL</i>
        involving currents 
        <i>i 
        <sub>R</sub>
        </i>
        ( 
        <i>t</i>
        ) and 
        <i>i 
        <sub>C</sub>
        </i>
        ( 
        <i>t</i>
        ) at node 
        <i>X</i>
        , 
        <i>1</i>
        from 
        <i>KVL</i>
        involving voltages 
        <i>v 
        <sub>in</sub>
        </i>
        ( 
        <i>t</i>
        ), 
        <i>v 
        <sub>R</sub>
        </i>
        ( 
        <i>t</i>
        ) 
        <i>,</i>
        and 
        <i>v 
        <sub>-</sub>
        </i>
        ( 
        <i>t</i>
        ), 
        <i>1</i>
        from 
        <i>KVL</i>
        involving voltages 
        <i>v 
        <sub>-</sub>
        </i>
        ( 
        <i>t</i>
        ), 
        <i>v 
        <sub>C</sub>
        </i>
        ( 
        <i>t</i>
        ) 
        <i>,</i>
        and 
        <i>v 
        <sub>out</sub>
        </i>
        ( 
        <i>t</i>
        ), 
        <i>1</i>
        equation from Ohm's Law, 
        <i>1</i>
        equation from the relationship between the voltage and
        current in the capacitor, and, finally, 
        <i>1</i>
        equation from the fact that the output voltage of the op
        amp is the difference between the two input voltages
        multiplied by the gain, 
        <i>A</i>
        of the op amp: 
        <i>v 
        <sub>out</sub>
        </i>
        ( 
        <i>t</i>
        ) 
        <i>= A</i>
        [ 
        <i>v 
        <sub>+</sub>
        </i>
        ( 
        <i>t</i>
        ) 
        <i>- v 
        <sub>-</sub>
        </i>
        ( 
        <i>t</i>
        )] 
        <i>= - A v 
        <sub>-</sub>
        </i>
        ( 
        <i>t</i>
        ) since 
        <i>v 
        <sub>+</sub>
        </i>
        ( 
        <i>t</i>
        ) is always zero. Combine these 
        <i>6</i>
        equations to show that:</p>
        <p style='margin-left:1.0in'>
          <m:math>
            <m:semantics>
              <m:mrow>
                <m:mfrac>
                  <m:mrow>
                    <m:mi>d</m:mi>
                    <m:msub>
                      <m:mi>v</m:mi>
                      <m:mrow>
                        <m:mi>o</m:mi>
                        <m:mi>u</m:mi>
                        <m:mi>t</m:mi>
                      </m:mrow>
                    </m:msub>
                    <m:mrow>
                      <m:mo>(</m:mo>
                      <m:mi>t</m:mi>
                      <m:mo>)</m:mo>
                    </m:mrow>
                  </m:mrow>
                  <m:mrow>
                    <m:mi>d</m:mi>
                    <m:mi>t</m:mi>
                  </m:mrow>
                </m:mfrac>
                <m:mtext>&#8201;</m:mtext>
                <m:mo>=</m:mo>
                <m:mtext>&#8201;</m:mtext>
                <m:mo>&#8722;</m:mo>
                <m:mtext>&#8201;</m:mtext>
                <m:mfrac>
                  <m:mn>1</m:mn>
                  <m:mrow>
                    <m:mi>R</m:mi>
                    <m:mtext>&#8201;</m:mtext>
                    <m:mi>C</m:mi>
                    <m:mrow>
                      <m:mo>(</m:mo>
                      <m:mrow>
                        <m:mn>1</m:mn>
                        <m:mo>+</m:mo>
                        <m:mfrac>
                          <m:mn>1</m:mn>
                          <m:mi>A</m:mi>
                        </m:mfrac>
                      </m:mrow>
                      <m:mo>)</m:mo>
                    </m:mrow>
                  </m:mrow>
                </m:mfrac>
                <m:mtext>&#8201;</m:mtext>
                <m:msub>
                  <m:mi>v</m:mi>
                  <m:mrow>
                    <m:mi>i</m:mi>
                    <m:mi>n</m:mi>
                  </m:mrow>
                </m:msub>
                <m:mrow>
                  <m:mo>(</m:mo>
                  <m:mi>t</m:mi>
                  <m:mo>)</m:mo>
                </m:mrow>
                <m:mo>&#8722;</m:mo>
                <m:mtext>&#8201;</m:mtext>
                <m:mfrac>
                  <m:mn>1</m:mn>
                  <m:mrow>
                    <m:mi>A</m:mi>
                    <m:mrow>
                      <m:mo>(</m:mo>
                      <m:mrow>
                        <m:mn>1</m:mn>
                        <m:mo>+</m:mo>
                        <m:mfrac>
                          <m:mn>1</m:mn>
                          <m:mi>A</m:mi>
                        </m:mfrac>
                      </m:mrow>
                      <m:mo>)</m:mo>
                    </m:mrow>
                    <m:mi>R</m:mi>
                    <m:mi>C</m:mi>
                  </m:mrow>
                </m:mfrac>
                <m:mtext>&#8201;</m:mtext>
                <m:msub>
                  <m:mi>v</m:mi>
                  <m:mrow>
                    <m:mi>o</m:mi>
                    <m:mi>u</m:mi>
                    <m:mi>t</m:mi>
                  </m:mrow>
                </m:msub>
                <m:mrow>
                  <m:mo>(</m:mo>
                  <m:mi>t</m:mi>
                  <m:mo>)</m:mo>
                </m:mrow>
              </m:mrow>
            </m:semantics>
          </m:math>
        </p>
        <p>Use the 
        <a href="../software/software.htm#EquationEditor"
        target="final_window">Equation Editor</a>
        Equation Editor in Word to write the equations and the
        steps in your solution in the document 
        <i>final.doc</i>
        .</p>
        <p>
          <b>During part 1 you should have inserted into the
          document 
          <i>final.doc</i>
          in a directory named 
          <i>final</i>
          on your hard disk:</b>
        </p>
        <ul type="disc">
          <li>
            <b>The 6 equations described above, together with
            explanatory text, and</b>
          </li>
          <li>
            <b>The derivation of the given equation, together
            with explanatory text.</b>
          </li>
        </ul>
      </li>
      <li>
        <p>(10 points) In ideal op amps, the gain 
        <i>A</i>
        approaches infinity. Take the limit as 
        <i>A</i>
        approaches infinity to show that, with an ideal op amp in
        the circuit above, the equation you just found simplifies
        to:</p>
        <p style='margin-left:1.0in'>
          <m:math>
            <m:semantics>
              <m:mrow>
                <m:mfrac>
                  <m:mrow>
                    <m:mi>d</m:mi>
                    <m:msub>
                      <m:mi>v</m:mi>
                      <m:mrow>
                        <m:mi>o</m:mi>
                        <m:mi>u</m:mi>
                        <m:mi>t</m:mi>
                      </m:mrow>
                    </m:msub>
                    <m:mrow>
                      <m:mo>(</m:mo>
                      <m:mi>t</m:mi>
                      <m:mo>)</m:mo>
                    </m:mrow>
                  </m:mrow>
                  <m:mrow>
                    <m:mi>d</m:mi>
                    <m:mi>t</m:mi>
                  </m:mrow>
                </m:mfrac>
                <m:mtext>&#8201;</m:mtext>
                <m:mo>=</m:mo>
                <m:mtext>&#8201;</m:mtext>
                <m:mo>&#8722;</m:mo>
                <m:mtext>&#8201;</m:mtext>
                <m:mfrac>
                  <m:mn>1</m:mn>
                  <m:mrow>
                    <m:mi>R</m:mi>
                    <m:mtext>&#8201;</m:mtext>
                    <m:mi>C</m:mi>
                  </m:mrow>
                </m:mfrac>
                <m:mtext>&#8201;</m:mtext>
                <m:msub>
                  <m:mi>v</m:mi>
                  <m:mrow>
                    <m:mi>i</m:mi>
                    <m:mi>n</m:mi>
                  </m:mrow>
                </m:msub>
                <m:mrow>
                  <m:mo>(</m:mo>
                  <m:mi>t</m:mi>
                  <m:mo>)</m:mo>
                </m:mrow>
              </m:mrow>
            </m:semantics>
          </m:math>
        </p>
        <p>Use the equation editor in Word to record your work in
        
        <i>final.doc</i>
        . In practical op amps, the gain, 
        <i>A</i>
        , is much larger than 
        <i>1</i>
        . For a 
        <i>741</i>
        op amp 
        <i>A</i>
        is at least 10,000. As a consequence, this expression for
        the gain holds with good accuracy when a 
        <i>741</i>
        op amp is used in the circuit above rather than an ideal
        op amp.</p>
        <p>
          <b>During part 2, you should have inserted into the
          document 
          <i>final.doc</i>
          the mathematical steps, together with explanatory text,
          that lead from the equation given in part 1 to the
          equation given in part 2.</b>
        </p>
      </li>
      <li>
        <p>(10 points) Note that the last equation shows that the
        derivative of the output voltage from the circuit above
        is directly proportional to the input voltage to the
        circuit. That means that the output voltage must be
        proportional to the integral of the input. Starting with
        the equation from part 
        <i>2</i>
        , use 
        <a href="../notes/antiderivatives.xml"
        target="final_window">indefinite integration</a>
        to show that:</p>
        <p style='margin-left:1.0in'>
          <m:math>
            <m:semantics>
              <m:mrow>
                <m:msub>
                  <m:mi>v</m:mi>
                  <m:mrow>
                    <m:mi>o</m:mi>
                    <m:mi>u</m:mi>
                    <m:mi>t</m:mi>
                  </m:mrow>
                </m:msub>
                <m:mrow>
                  <m:mo>(</m:mo>
                  <m:mi>t</m:mi>
                  <m:mo>)</m:mo>
                </m:mrow>
                <m:mtext>&#8201;</m:mtext>
                <m:mo>=</m:mo>
                <m:mtext>&#8201;</m:mtext>
                <m:mo>&#8722;</m:mo>
                <m:mtext>&#8201;</m:mtext>
                <m:mfrac>
                  <m:mn>1</m:mn>
                  <m:mrow>
                    <m:mi>R</m:mi>
                    <m:mtext>&#8201;</m:mtext>
                    <m:mi>C</m:mi>
                  </m:mrow>
                </m:mfrac>
                <m:mtext>&#8201;</m:mtext>
                <m:mrow>
                  <m:mo>&#8747;</m:mo>
                  <m:mrow>
                    <m:msub>
                      <m:mi>v</m:mi>
                      <m:mrow>
                        <m:mi>i</m:mi>
                        <m:mi>n</m:mi>
                      </m:mrow>
                    </m:msub>
                    <m:mrow>
                      <m:mo>(</m:mo>
                      <m:mi>t</m:mi>
                      <m:mo>)</m:mo>
                    </m:mrow>
                    <m:mi>d</m:mi>
                    <m:mi>t</m:mi>
                  </m:mrow>
                </m:mrow>
                <m:mo>+</m:mo>
                <m:mi>K</m:mi>
              </m:mrow>
            </m:semantics>
          </m:math>
        </p>
        <p>where 
        <i>K</i>
        is a constant of integration. The constant 
        <i>K</i>
        corresponds to a 
        <i>dc</i>
        voltage that often is zero and is usually not
        important.</p>
        <p>The negative sign before the integral indicates that
        the output of the integrator is "upside down," so this
        integrator is an example of an 
        <i>inverting</i>
        integrator. If inversion is a problem in a particular
        application, we can feed the output of the inverting
        integrator into an inverting amplifier and make the
        output right side up. Use the equation editor in Word to
        record your work in 
        <i>final.doc</i>
        .</p>
        <p>The desire to make this last equation hold true drove
        the original development of operational amplifiers. It is
        ironic that just at the time that integrated circuit
        technology allowed manufacture of inexpensive op amps
        with good quality, their original application as
        integrators in analog computers largely disappeared as
        digital computers replaced analog computers. Not only
        other applications for integrators soon emerged, however,
        but also countless other applications of op amps in
        amplifiers and noise filters generated enough demand to
        ensure the eventual commercial availability of a variety
        of op amp chips at reasonable costs.</p>
        <p>
          <b>During part 3, you should have inserted into the
          document 
          <i>final.doc</i>
          the mathematical steps, together with explanatory text,
          that lead from the equation given in part 2 to the
          equation given in part 3.</b>
        </p>
      </li>
      <li>
        <p>(30 points) Construct the circuit you designed by
        soldering the components into a 
        <i>General-Purpose IC PC Board (RadioShack Cat. No.
        276-150)</i>
        , or a similar board. Life will be simpler for you if you
        use an 
        <i>8-Pin Low-Profile Socket (RadioShack Cat. No.
        276-1995)</i>
        instead of soldering the 
        <i>741</i>
        op amp chip directly into the PC board. Use the circuit
        diagram shown below, which includes 
        <i>3</i>
        more resistors than the circuit we considered above.</p>
        <p>
          <img src="./final_files/image004.jpg" />
        </p>
        <p>Here is a possible configuration on the printed
        circuit board ( 
        <a
        href="http://www.ece.msstate.edu/classes/ece1002/final/finalPCBtop.jpg"
         target="final_window">top view</a>
        , 
        <a
        href="http://www.ece.msstate.edu/classes/ece1002/final/finalPCBbottom.jpg"
         target="final_window">bottom view</a>
        ).</p>
        <p>The circuit and component values were chosen to
        accommodate periodic inputs, such as sinusoids and square
        waves, that have zero average value and contain
        frequencies of a few thousand 
        <i>Hz</i>
        . The 
        <i>100,000 Ohm</i>
        resistor connected across the capacitor is chosen large
        enough to have little effect on the operation of the
        circuit other than to discharge the capacitor slowly in
        case any charge should accumulate on it. In effect, this
        resistor maintains a value of zero for 
        <i>K</i>
        , the constant of integration that appeared in an earlier
        equation for the output voltage of the integrator.</p>
        <p>The 
        <i>10,000 Ohm</i>
        resistor across the output terminals, which in fact has
        little effect on the operation of the circuit, represents
        the effect of some circuit that would draw current from
        the output of the integrator when it is used in a
        practical application.</p>
        <p>The 
        <i>10,000 Ohm</i>
        resistor inserted between the non-inverting (+) input to
        the op amp and ground roughly matches the resistance at
        the inverting input so that any non-zero leakage currents
        at the input terminals of practical op amps produce
        approximately equal 
        <i>dc</i>
        voltages at the inverting and non-inverting inputs which,
        because the op amp is a differential amplifier, cancel
        each other out as far as any effect on the output voltage
        is concerned.</p>
        <p>This circuit diagram also includes the 
        <i>9V</i>
        batteries that are necessary for the 
        <i>741</i>
        chip to operate, but were not shown, for simplicity, in
        the earlier diagram.</p>
        <p>
          <b>During part 4, you should have constructed the
          circuit in the diagram shown in part 4. Connect the 9V
          batteries only during testing. Do not submit them.</b>
        </p>
      </li>
      <li>
        <p>(10 points) Use the Capture part of OrCAD PSpice 
        <sup>&#174;</sup>
        to draw and then simulate this circuit. In a folder 
        <i>final</i>
        on your hard drive, create an OrCAD PSpice simulation
        project named 
        <i>finalsine</i>
        in which the sinusoidal input voltage has a frequency of 
        <i>2000Hz</i>
        and an amplitude of 
        <i>1V</i>
        . Run the simulation for times between 
        <i>0</i>
        and 
        <i>10ms</i>
        so that you can see the first 20 cycles of the output
        waveform.</p>
        <p>Include in the Word document screen shots of the
        schematic and of a screen from OrCAD PSpice 
        <sup>&#174;</sup>
        that shows simultaneously the input voltage and the
        simulated output voltage. Notice that during startup, the
        capacitor becomes charged and that the 
        <i>100,000 Ohm</i>
        resistor requires a few cycles to drain off this initial
        charge. A smaller value for this resistor would drain off
        the charge more quickly, but could interfere more with
        the basic operation of the integrator circuit. For
        reading values from the simulation, you may wish to
        change the OrCAD PSpice 
        <sup>&#174;</sup>
        settings to display only the last few cycles of the
        simulation in more detail.</p>
        <p>Also include in the Word document a comparison of the
        relative amplitudes and phases of the output voltage with
        the input voltage and explain how these quantities are
        consistent with the output voltage being proportional to
        the integral of the input voltage. To compare the
        relative amplitude and phase of the input and output of
        the integrator, use the fact that if</p>
        <p style='margin-left:1.0in'>
          <m:math>
            <m:semantics>
              <m:mrow>
                <m:msub>
                  <m:mi>v</m:mi>
                  <m:mrow>
                    <m:mi>i</m:mi>
                    <m:mi>n</m:mi>
                  </m:mrow>
                </m:msub>
                <m:mrow>
                  <m:mo>(</m:mo>
                  <m:mi>t</m:mi>
                  <m:mo>)</m:mo>
                </m:mrow>
                <m:mo>=</m:mo>
                <m:mi>M</m:mi>
                <m:mi>sin</m:mi>
                <m:mo>&#8289;</m:mo>
                <m:mrow>
                  <m:mo>(</m:mo>
                  <m:mrow>
                    <m:mn>2</m:mn>
                    <m:mi>&#960;</m:mi>
                    <m:mi>f</m:mi>
                    <m:mtext>&#8201;</m:mtext>
                    <m:mi>t</m:mi>
                  </m:mrow>
                  <m:mo>)</m:mo>
                </m:mrow>
              </m:mrow>
            </m:semantics>
          </m:math>
        </p>
        <p>where 
        <i>M</i>
        is the amplitude of the sinusoid and 
        <i>f</i>
        is its frequency in Hertz, then</p>
        <p style='margin-left:1.0in'>
          <m:math>
            <m:semantics>
              <m:mrow>
                <m:mo>&#8722;</m:mo>
                <m:mrow>
                  <m:mo>&#8747;</m:mo>
                  <m:mrow>
                    <m:msub>
                      <m:mi>v</m:mi>
                      <m:mrow>
                        <m:mi>i</m:mi>
                        <m:mi>n</m:mi>
                      </m:mrow>
                    </m:msub>
                    <m:mrow>
                      <m:mo>(</m:mo>
                      <m:mi>t</m:mi>
                      <m:mo>)</m:mo>
                    </m:mrow>
                    <m:mi>d</m:mi>
                    <m:mi>t</m:mi>
                  </m:mrow>
                </m:mrow>
                <m:mo>=</m:mo>
                <m:mfrac>
                  <m:mi>M</m:mi>
                  <m:mrow>
                    <m:mn>2</m:mn>
                    <m:mi>&#960;</m:mi>
                    <m:mi>f</m:mi>
                  </m:mrow>
                </m:mfrac>
                <m:mi>cos</m:mi>
                <m:mo>&#8289;</m:mo>
                <m:mrow>
                  <m:mo>(</m:mo>
                  <m:mrow>
                    <m:mn>2</m:mn>
                    <m:mi>&#960;</m:mi>
                    <m:mi>f</m:mi>
                    <m:mtext>&#8201;</m:mtext>
                    <m:mi>t</m:mi>
                  </m:mrow>
                  <m:mo>)</m:mo>
                </m:mrow>
                <m:mo>=</m:mo>
                <m:mfrac>
                  <m:mi>M</m:mi>
                  <m:mrow>
                    <m:mn>2</m:mn>
                    <m:mi>&#960;</m:mi>
                    <m:mi>f</m:mi>
                  </m:mrow>
                </m:mfrac>
                <m:mi>sin</m:mi>
                <m:mo>&#8289;</m:mo>
                <m:mrow>
                  <m:mo>(</m:mo>
                  <m:mrow>
                    <m:mn>2</m:mn>
                    <m:mi>&#960;</m:mi>
                    <m:mi>f</m:mi>
                    <m:mtext>&#8201;</m:mtext>
                    <m:mi>t</m:mi>
                    <m:mo>+</m:mo>
                    <m:mfrac>
                      <m:mi>&#960;</m:mi>
                      <m:mn>2</m:mn>
                    </m:mfrac>
                  </m:mrow>
                  <m:mo>)</m:mo>
                </m:mrow>
              </m:mrow>
            </m:semantics>
          </m:math>
        </p>
        <p>so that for the case 
        <i>K=0</i>
        ,</p>
        <p style='margin-left:1.0in'>
          <m:math>
            <m:semantics>
              <m:mrow>
                <m:msub>
                  <m:mi>v</m:mi>
                  <m:mrow>
                    <m:mi>o</m:mi>
                    <m:mi>u</m:mi>
                    <m:mi>t</m:mi>
                  </m:mrow>
                </m:msub>
                <m:mrow>
                  <m:mo>(</m:mo>
                  <m:mi>t</m:mi>
                  <m:mo>)</m:mo>
                </m:mrow>
                <m:mtext>&#8201;</m:mtext>
                <m:mo>=</m:mo>
                <m:mtext>&#8201;</m:mtext>
                <m:mo>&#8722;</m:mo>
                <m:mtext>&#8201;</m:mtext>
                <m:mfrac>
                  <m:mn>1</m:mn>
                  <m:mrow>
                    <m:mi>R</m:mi>
                    <m:mtext>&#8201;</m:mtext>
                    <m:mi>C</m:mi>
                  </m:mrow>
                </m:mfrac>
                <m:mtext>&#8201;</m:mtext>
                <m:mrow>
                  <m:mo>&#8747;</m:mo>
                  <m:mrow>
                    <m:msub>
                      <m:mi>v</m:mi>
                      <m:mrow>
                        <m:mi>i</m:mi>
                        <m:mi>n</m:mi>
                      </m:mrow>
                    </m:msub>
                    <m:mrow>
                      <m:mo>(</m:mo>
                      <m:mi>t</m:mi>
                      <m:mo>)</m:mo>
                    </m:mrow>
                    <m:mi>d</m:mi>
                    <m:mi>t</m:mi>
                  </m:mrow>
                </m:mrow>
                <m:mo>=</m:mo>
                <m:mfrac>
                  <m:mn>1</m:mn>
                  <m:mrow>
                    <m:mi>R</m:mi>
                    <m:mtext>&#8201;</m:mtext>
                    <m:mi>C</m:mi>
                  </m:mrow>
                </m:mfrac>
                <m:mtext>&#8201;</m:mtext>
                <m:mfrac>
                  <m:mi>M</m:mi>
                  <m:mrow>
                    <m:mn>2</m:mn>
                    <m:mi>&#960;</m:mi>
                    <m:mi>f</m:mi>
                  </m:mrow>
                </m:mfrac>
                <m:mi>sin</m:mi>
                <m:mo>&#8289;</m:mo>
                <m:mrow>
                  <m:mo>(</m:mo>
                  <m:mrow>
                    <m:mn>2</m:mn>
                    <m:mi>&#960;</m:mi>
                    <m:mi>f</m:mi>
                    <m:mtext>&#8201;</m:mtext>
                    <m:mi>t</m:mi>
                    <m:mo>+</m:mo>
                    <m:mfrac>
                      <m:mi>&#960;</m:mi>
                      <m:mn>2</m:mn>
                    </m:mfrac>
                  </m:mrow>
                  <m:mo>)</m:mo>
                </m:mrow>
              </m:mrow>
            </m:semantics>
          </m:math>
        </p>
        <p>That is, the inverted integral of a sinusoid is a
        sinusoid with the same frequency, with a phase that leads
        the original sinusoid by 
        <i>90&#176;</i>
        , and with amplitude relative to the input of</p>
        <p style='margin-left:1.0in'>
          <m:math>
            <m:semantics>
              <m:mrow>
                <m:mtext>&#8201;</m:mtext>
                <m:mfrac>
                  <m:mrow>
                    <m:mtext>output</m:mtext>
                    <m:mtext>&#8201;</m:mtext>
                    <m:mtext>amplitude</m:mtext>
                  </m:mrow>
                  <m:mrow>
                    <m:mtext>input</m:mtext>
                    <m:mtext>&#8201;</m:mtext>
                    <m:mtext>amplitude</m:mtext>
                  </m:mrow>
                </m:mfrac>
                <m:mtext>&#8201;</m:mtext>
                <m:mo>=</m:mo>
                <m:mrow>
                  <m:mrow>
                    <m:mfrac>
                      <m:mn>1</m:mn>
                      <m:mrow>
                        <m:mi>R</m:mi>
                        <m:mtext>&#8201;</m:mtext>
                        <m:mi>C</m:mi>
                      </m:mrow>
                    </m:mfrac>
                    <m:mtext>&#8201;</m:mtext>
                    <m:mfrac>
                      <m:mi>M</m:mi>
                      <m:mrow>
                        <m:mn>2</m:mn>
                        <m:mi>&#960;</m:mi>
                        <m:mi>f</m:mi>
                      </m:mrow>
                    </m:mfrac>
                  </m:mrow>
                  <m:mo>/</m:mo>
                  <m:mi>M</m:mi>
                </m:mrow>
                <m:mo>=</m:mo>
                <m:mtext>&#8201;</m:mtext>
                <m:mfrac>
                  <m:mn>1</m:mn>
                  <m:mrow>
                    <m:mn>2</m:mn>
                    <m:mi>&#960;</m:mi>
                    <m:mi>R</m:mi>
                    <m:mi>C</m:mi>
                    <m:mi>f</m:mi>
                  </m:mrow>
                </m:mfrac>
              </m:mrow>
            </m:semantics>
          </m:math>
        </p>
        <p>Use the equation editor to include your calculations
        in the Word file. From the Capture part of OrCAD PSpice 
        <sup>&#174;</sup>
        , save the project 
        <i>finalsine</i>
        in the folder named 
        <i>final</i>
        on your hard disk.</p>
        <p>
          <b>During part 5 you should have inserted into the
          document 
          <i>final.doc</i>
          :</b>
        </p>
        <ul type="disc">
          <li>
            <p>
              <b>A Capture screen that shows the circuit with a 
              <i>2000Hz</i>
              sinusoidal source,</b>
            </p>
          </li>
          <li>
            <p>
              <b>An OrCAD PSpice screen shot that shows the
              simulated input and output for the integrator
              circuit with a 
              <i>2000Hz</i>
              sinusoidal input that has an amplitude of 
              <i>1V</i>
              ,</b>
            </p>
          </li>
          <li>
            <p>
              <b>A discussion, including equations, that shows
              that the relative amplitudes and phases of the
              output voltage and the input voltage are consistent
              with the output voltage being proportional to the
              integral of the input voltage.</b>
            </p>
          </li>
        </ul>
        <p>
          <b>During part 5, you should have saved the project 
          <i>finalsine</i>
          in the directory 
          <i>final</i>
          on your hard disk.</b>
        </p>
      </li>
      <li>
        <p>(10 points) Repeat part 
        <i>5</i>
        for a 
        <i>2000Hz</i>
        square wave with amplitude of 
        <i>1V</i>
        by creating a new OrCAD PSpice project, 
        <i>finalsquare</i>
        based on the project 
        <i>finalsine</i>
        , in the folder 
        <i>final</i>
        on your hard drive. Do not include another screenshot of
        the revised schematic, however.</p>
        <p>The output waveform should be triangular whenever the
        input waveform is a square wave. In the Word file,
        discuss why.</p>
        <p>Also, compare the simultaneous input and output
        waveforms and discuss the degree to which they are
        consistent with the output voltage being proportional to
        the integral of the input voltage for this particular
        waveform. Specifically, derive the result</p>
        <p style='margin-left:1.0in'>
          <m:math>
            <m:semantics>
              <m:mrow>
                <m:msub>
                  <m:mi>v</m:mi>
                  <m:mrow>
                    <m:mi>o</m:mi>
                    <m:mi>u</m:mi>
                    <m:mi>t</m:mi>
                  </m:mrow>
                </m:msub>
                <m:mrow>
                  <m:mo>(</m:mo>
                  <m:mi>t</m:mi>
                  <m:mo>)</m:mo>
                </m:mrow>
                <m:mtext>&#8201;</m:mtext>
                <m:mo>=</m:mo>
                <m:mtext>&#8201;</m:mtext>
                <m:mo>&#8722;</m:mo>
                <m:mtext>&#8201;</m:mtext>
                <m:mfrac>
                  <m:mn>1</m:mn>
                  <m:mrow>
                    <m:mi>R</m:mi>
                    <m:mtext>&#8201;</m:mtext>
                    <m:mi>C</m:mi>
                  </m:mrow>
                </m:mfrac>
                <m:mtext>&#8201;</m:mtext>
                <m:mrow>
                  <m:mo>&#8747;</m:mo>
                  <m:mrow>
                    <m:msub>
                      <m:mi>v</m:mi>
                      <m:mrow>
                        <m:mi>i</m:mi>
                        <m:mi>n</m:mi>
                      </m:mrow>
                    </m:msub>
                    <m:mrow>
                      <m:mo>(</m:mo>
                      <m:mi>t</m:mi>
                      <m:mo>)</m:mo>
                    </m:mrow>
                    <m:mi>d</m:mi>
                    <m:mi>t</m:mi>
                  </m:mrow>
                </m:mrow>
                <m:mo>=</m:mo>
                <m:mrow>
                  <m:mo>{</m:mo>
                  <m:mrow>
                    <m:mtable>
                      <m:mtr>
                        <m:mtd>
                          <m:mrow>
                            <m:mo>&#8722;</m:mo>
                            <m:mfrac>
                              <m:mn>1</m:mn>
                              <m:mrow>
                                <m:mi>R</m:mi>
                                <m:mtext>&#8201;</m:mtext>
                                <m:mi>C</m:mi>
                              </m:mrow>
                            </m:mfrac>
                            <m:mi>t</m:mi>
                            <m:mo>,</m:mo>
                            <m:mtext>&#8201;</m:mtext>
                            <m:mtext>&#8201;</m:mtext>
                            <m:mtext>&#8201;</m:mtext>
                            <m:mtext>&#8201;</m:mtext>
                            <m:mtext>&#8201;</m:mtext>
                            <m:mtext>&#8201;</m:mtext>
                            <m:mtext>when</m:mtext>
                            <m:mtext>&#8201;</m:mtext>
                            <m:msub>
                              <m:mi>v</m:mi>
                              <m:mrow>
                                <m:mi>i</m:mi>
                                <m:mi>n</m:mi>
                              </m:mrow>
                            </m:msub>
                            <m:mrow>
                              <m:mo>(</m:mo>
                              <m:mi>t</m:mi>
                              <m:mo>)</m:mo>
                            </m:mrow>
                            <m:mo>=</m:mo>
                            <m:mo>+</m:mo>
                            <m:mn>1</m:mn>
                            <m:mi>V</m:mi>
                          </m:mrow>
                        </m:mtd>
                      </m:mtr>
                      <m:mtr>
                        <m:mtd>
                          <m:mrow>
                            <m:mo>+</m:mo>
                            <m:mfrac>
                              <m:mn>1</m:mn>
                              <m:mrow>
                                <m:mi>R</m:mi>
                                <m:mtext>&#8201;</m:mtext>
                                <m:mi>C</m:mi>
                              </m:mrow>
                            </m:mfrac>
                            <m:mi>t</m:mi>
                            <m:mo>,</m:mo>
                            <m:mtext>&#8201;</m:mtext>
                            <m:mtext>&#8201;</m:mtext>
                            <m:mtext>&#8201;</m:mtext>
                            <m:mtext>&#8201;</m:mtext>
                            <m:mtext>&#8201;</m:mtext>
                            <m:mtext>&#8201;</m:mtext>
                            <m:mtext>when</m:mtext>
                            <m:mtext>&#8201;</m:mtext>
                            <m:msub>
                              <m:mi>v</m:mi>
                              <m:mrow>
                                <m:mi>i</m:mi>
                                <m:mi>n</m:mi>
                              </m:mrow>
                            </m:msub>
                            <m:mrow>
                              <m:mo>(</m:mo>
                              <m:mi>t</m:mi>
                              <m:mo>)</m:mo>
                            </m:mrow>
                            <m:mo>=</m:mo>
                            <m:mo>&#8722;</m:mo>
                            <m:mn>1</m:mn>
                            <m:mi>V</m:mi>
                          </m:mrow>
                        </m:mtd>
                      </m:mtr>
                    </m:mtable>
                  </m:mrow>
                </m:mrow>
              </m:mrow>
            </m:semantics>
          </m:math>
        </p>
        <p>and use it to calculate the theoretically expected
        slopes for the output waveform and compare these values
        with ones that you read from the simulated output
        waveform. (The units of the product 
        <i>RC</i>
        turn out to be 
        <i>seconds</i>
        , so the slopes &#177; 
        <i>1V/RC</i>
        of the triangular waveform have units of 
        <i>V/s</i>
        .) Use the equation editor to include your calculations
        in the Word file.</p>
        <p>From the Capture part of OrCAD PSpice 
        <sup>&#174;</sup>
        , save the project 
        <i>finalsquare</i>
        in the folder named 
        <i>final</i>
        on your hard disk.</p>
        <p>
          <b>During part 6 you should have inserted into the
          document 
          <i>final.doc</i>
          :</b>
        </p>
        <ul type="disc">
          <li>
            <p>
              <b>An OrCAD PSpice screen shot that shows the
              simulated input and output for the integrator
              circuit with a 
              <i>2000Hz</i>
              square wave input,</b>
            </p>
          </li>
          <li>
            <p>
              <b>A derivation of the equation above that includes
              explanatory text, and</b>
            </p>
          </li>
          <li>
            <p>
              <b>A discussion, based on the equation you derived
              in part 6, about why a square wave input to an
              integrator circuit produces a triangular wave as an
              output.</b>
            </p>
          </li>
        </ul>
        <p>
          <b>During part 6, you should have saved the OrCAD
          PSpice project, 
          <i>finalsquare</i>
          , in the directory 
          <i>final</i>
          on your hard disk.</b>
        </p>
      </li>
      <li>
        <p>(10 points) To begin investigating the performance of
        your integrator circuit experimentally open one instance
        of Cool Edit and generate a 
        <i>2000Hz</i>
        sinusoidal signal 
        <i>1sec</i>
        or so in duration. You need NOT save this signal to disk
        to play it and use it as an input to the integrator. You
        will connect the output of your sound card to the input
        of your integrator and play this sinusoidal file to
        generate an input signal for the integrator. Next, open a
        second instance of Cool Edit for recording the output
        signal from the integrator.</p>
        <p>With your audio cables, connect the microphone input
        of your laptop to the output of the integrator, and
        connect the headphone output of your laptop to the input
        of the integrator. Specifically, connect the appropriate
        red alligator clips to the input and output of your
        integrator and both black alligator clips to ground.
        Start playing the sinusoidal signal from the first
        instance of Cool Edit and, while it is playing, use the
        second instance of Cool Edit to record the output
        voltage. If necessary, adjust the playback volume from
        your laptop so that the maximum amplitude of output
        voltage is roughly 75% of the display range in the Cool
        Edit window. If the output voltage is 100% of the display
        or larger, the sound card may become overloaded and thus
        record a distorted version of the true output voltage.
        Save this WAV file as 
        <i>finalVoutsine.wav</i>
        in the folder 
        <i>final</i>
        on your hard disk. Into the Word file 
        <i>final.doc</i>
        , insert a screen shot of the Cool Edit screen that shows
        the recorded output voltage of the integrator. Then zoom
        in so that only a few cycles of the output waveform are
        displayed and include a screenshot of this view, as
        well.</p>
        <p>Next, record the input to your integrator. Be careful
        not change the playback volume from that you used to
        record the output of the integrator. Move the red
        alligator clip that connects to the microphone input 
        <i>from</i>
        the output terminal of the amplifier 
        <i>to</i>
        the input terminal of the amplifier. (The black alligator
        clip, connected to ground, can remain in the same place.)
        Then record the input voltage as you play the sinusoidal
        signal again. Save this WAV file as 
        <i>finalVinsine.wav</i>
        in the folder 
        <i>final</i>
        on your hard disk. In the Word file 
        <i>final.doc</i>
        , insert a screen shot of the Cool Edit screen that shows
        the recording of the input voltage to the integrator and
        verify that it is a sinusoid of the proper frequency.</p>
        <p>In the Word file, include a discussion that compares
        the ratio of the measured input and output sinusoidal
        amplitudes with the values that you obtained in part 
        <i>5</i>
        from simulation and from analytical calculation. (Because
        many laptops do not record in stereo, we cannot record
        simultaneously the input and output to the integrator in
        separate stereo channels and thus we cannot compare the
        relative phases of the input and output signals. That
        could be done with a desktop computer that can record in
        stereo, although that would require an additional cable
        with alligator clips.)</p>
        <p>
          <b>During part 7 you should have inserted into the
          document 
          <i>final.doc</i>
          :</b>
        </p>
        <ul type="disc">
          <li>
            <p>
              <b>A screen shot of the Cool Edit screen that shows
              the recorded output voltage of the integrator when
              the input voltage is a 
              <i>2000Hz</i>
              sine wave about 1 second in duration,</b>
            </p>
          </li>
          <li>
            <p>
              <b>A screen shot of the Cool Edit screen that shows
              a few cycles of the recorded output voltage of the
              integrator when the input voltage is a 
              <i>2000Hz</i>
              sine wave</b>
            </p>
          </li>
          <li>
            <p>
              <b>A screen shot of the Cool Edit screen that shows
              the recorded input voltage of the integrator,</b>
            </p>
          </li>
          <li>
            <p>
              <b>A screen shot of the Cool Edit screen that shows
              a few cycles of the recorded input voltage of the
              integrator, together with discussion and
              calculation that verify the input is a sinusoid
              with the proper frequency, and</b>
            </p>
          </li>
          <li>
            <p>
              <b>A comparison of the ratio of the measured input
              and output sinusoidal amplitudes with the values
              that you obtained in part 
              <i>5</i>
              from simulation and from analytical
              calculation.</b>
            </p>
          </li>
        </ul>
        <p>
          <b>During part 7, you should have saved the Cool Edit
          file that shows the output waveform of your circuit
          when the input is a 
          <i>2000Hz</i>
          sine wave as 
          <i>finalVoutsine.wav</i>
          in the directory 
          <i>final</i>
          on your hard disk.</b>
        </p>
        <p>
          <b>During part 7, you should have saved the Cool Edit
          file that shows the input waveform to your circuit as 
          <i>finalVinsine.wav</i>
          in the directory 
          <i>final</i>
          on your hard disk.</b>
        </p>
      </li>
      <li>
        <p>(10 points) Repeat part 
        <i>7</i>
        with a 
        <i>2000Hz</i>
        square wave as the input to the integrator. Save the
        input and output WAV files as 
        <i>finalVinsquare.wav</i>
        and as 
        <i>finalVoutsquare.wav</i>
        in the folder 
        <i>final</i>
        on your hard disk. Include screenshots of the recorded
        output and input of the integrator, as well as zoomed
        screenshots that show only a few cycles of the output and
        input waveforms. In the Word file, compare the
        experimental input and output waveforms with those that
        resulted from simulation in part 
        <i>6</i>
        .</p>
        <p>
          <b>During part 8 you should have inserted into the
          document 
          <i>final.doc</i>
          :</b>
        </p>
        <ul type="disc">
          <li>
            <p>
              <b>A screen shot of the Cool Edit screen that shows
              the recorded output voltage of the integrator when
              the input voltage is a 
              <i>2000Hz</i>
              square wave about 1 second in duration,</b>
            </p>
          </li>
          <li>
            <p>
              <b>A screen shot of the Cool Edit screen that shows
              a few cycles of the recorded output voltage of the
              integrator when the input voltage is a 
              <i>2000Hz</i>
              square wave</b>
            </p>
          </li>
          <li>
            <p>
              <b>A screen shot of the Cool Edit screen that shows
              the recorded input voltage of the integrator,</b>
            </p>
          </li>
          <li>
            <p>
              <b>A screen shot of the Cool Edit screen that shows
              a few cycles of the recorded input voltage of the
              integrator, together with discussion and
              calculation that verify the input is a square wave
              with the proper frequency, and</b>
            </p>
          </li>
          <li>
            <p>
              <b>A discussion that compares the experimental
              input and output waveforms from part 8 with those
              that resulted from simulation in part 6.</b>
            </p>
          </li>
        </ul>
        <p>
          <b>During part 8, you should have saved the Cool Edit
          file that shows the output waveform of your circuit
          when the input is a 
          <i>2000Hz</i>
          square wave as 
          <i>finalVoutsquare.wav</i>
          in the directory 
          <i>final</i>
          on your hard disk.</b>
        </p>
        <p>
          <b>During part 8, you should have saved the Cool Edit
          file that shows the input waveform to your circuit as 
          <i>finalVinsquare.wav</i>
          in the directory 
          <i>final</i>
          on your hard disk.</b>
        </p>
      </li>
    </ol>
    <p>For the final project, use ZIP utility software, such as 
    <i>WinZip</i>
    , to prepare a ZIP file named 
    <i>final.zip</i>
    that includes all files that you have placed in the directory
    
    <i>final</i>
    on your hard disk. Specifically, 
    <i>final.zip</i>
    should include the following files:</p>
    <ul>
      <li>
        <i>finalsine.opj</i>
      </li>
      <li>
        <i>FINALSINE.DSN</i>
      </li>
      <li>
        <i>FINALSINE_0.DBK</i>
      </li>
      <li>
      <i>finalsine-PSpiceFiles</i>
      (non-empty folder)</li>
      <li>
        <i>finalsquare.opj</i>
      </li>
      <li>
        <i>FINALSQUARE.DSN</i>
      </li>
      <li>
        <i>FINALSQUARE_0.DBK</i>
      </li>
      <li>
      <i>finalsquare-PSpiceFiles</i>
      (non-empty folder)</li>
      <li>
        <i>finalVinsine.wav</i>
      </li>
      <li>
        <i>finalVoutsine.wav</i>
      </li>
      <li>
        <i>finalVinsquare.wav</i>
      </li>
      <li>
        <i>finalVoutsquare.wav</i>
      </li>
      <li>
        <i>final.doc</i>
      </li>
    </ul>
    <p>After you have made the ZIP file, go to the homework
    submission page, 
    <a
    href="http://www.ece.msstate.edu/courses/homework/submit.html"
     target="final_window">
    http://www.ece.msstate.edu/courses/homework/submit.html</a>
    , and submit 
    <i>final.zip</i>
    .</p>
    <p>Submit your circuit in the Ziploc 
    <sup>&#174;</sup>
    bag provided. Write your name, NetID, and e-mail address on
    the bag's label.</p>
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